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1
a·b =
x
1
y
1
+
x
2
y
2
Yes
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1
a·b =
(
x
1
+
y
1
)· (
x
2
+
y
2
)
No
Edit
Delete
1
a·b =
(
x
1
+
y
1
)· (
x
2
+
y
2
)
No
Edit
Delete
1
a·b =
x
1
y
2
+
x
2
y
1
No
Edit
Delete